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计算:(log23)2?4log23+4+log224=______

(log23)2+4log123+4?log213=(log23)2?4log23+4+log23=(log23?2)2+log23=2?log23+log23=2.故答案为2.

2723-2log23×log218+log23×log34=9-3×(-3)+lg3lg2×lg4lg3=9+9+2=20.故答案为:20.

这个是对数公式

∵3 log31+log248-log23=1+log2(48÷3)=1+4=5.故答案为:5.

7*log78=8 log67*log78就是log68,,以此类推,,就是log28

(94)? 12+log89×log332=23+23log23×5log32=23+103=4.故答案为:4.

loga(M^n)=nlogaM log(a^n)(M)=1/nlogaM log49=log(2^2)(3^2)=2/2log23=log23

log2(47×25)+log26-log23=log247+log225+log263=14+5+1=20故答案为:20

2log23+log(2+3)(3-2)2+102+lg2=2log32log22-2log(2+3)-1(2+3)-102×2=9-2-200=-193故答案为:-193.

[log3(2)+log2(3)]^2-log3(2)/log2(3)-log2(3)/log3(2) =[log3(2)+log2(3)]^2-[1/log2(3)]/log2(3)-[1/log3(2)]/log3(2) =[1/log2(3)+1/log3(2)]^2-[1/log2(3)]^2-[1/log3(2)]^2 =2/[log2(3)*log3(2)] =2

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