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计算log2(47×25)+log26%log23=______

log2(47×25)+log26-log23=log247+log225+log263=14+5+1=20故答案为:20

由于log23>log22=1,log32<log33=1,∴log23>log32,故答案为>.

因为y=log2x,是单调增函数,所以log25>log23.故答案为:>.

loga(M^n)=nlogaM log(a^n)(M)=1/nlogaM log49=log(2^2)(3^2)=2/2log23=log23

本题结果为3√3.

[log3(2)+log2(3)]^2-log3(2)/log2(3)-log2(3)/log3(2) =[log3(2)+log2(3)]^2-[1/log2(3)]/log2(3)-[1/log3(2)]/log3(2) =[1/log2(3)+1/log3(2)]^2-[1/log2(3)]^2-[1/log3(2)]^2 =2/[log2(3)*log3(2)] =2

:(log23)2?4log23+4+log224=(log23?2)2+log224=(log243)2+log224=log243+log224=log243×24=log232=5.故答案为5.

这个是对数公式

∵3 log31+log248-log23=1+log2(48÷3)=1+4=5.故答案为:5.

2log23+log(2+3)(3-2)2+102+lg2=2log32log22-2log(2+3)-1(2+3)-102×2=9-2-200=-193故答案为:-193.

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