mpjx.net
当前位置:首页 >> 计算log2(47×25)+log26%log23=______ >>

计算log2(47×25)+log26%log23=______

log2(47×25)+log26-log23=log247+log225+log263=14+5+1=20故答案为:20

[log21]=0,[log22]=[log23]=1,[log24]=[log25]=…=[log27]=2,[log28]=[log29]=…=[log215]=3,[log216]=[log217]=…=[log231]=4[log232]=5.∴[log21]+[log22]+[log23]+[log24]+…+[log232]=0+1×2+2×4+3×8+4×16+5=103.故答案为:103.

换底公式知道吗,还有loga^n和nloga相等,去算一下吧,不懂再说呗

[log3(2)+log2(3)]^2-log3(2)/log2(3)-log2(3)/log3(2) =[log3(2)+log2(3)]^2-[1/log2(3)]/log2(3)-[1/log3(2)]/log3(2) =[1/log2(3)+1/log3(2)]^2-[1/log2(3)]^2-[1/log3(2)]^2 =2/[log2(3)*log3(2)] =2

这个是对数公式

本题结果为3√3.

(1/2)^log23 =2^[-(lg2 3)]=2^[-(lg2 3)]=2^(lg2 1/3)=1/3

log2底3=log4底9 3/2=log4底^3/2=log4底8 因为log4底9>log4底8>log4底5 log4底5

log即以10为底的对数 如N=50,则log50=log(100/2)=log100-log2=2-log2=2-0.301=1.699 1+3.23log50=1+3.23×1.699=6.48777 若N=100,则1+3.23log100=1+3.23×2=7.46

由x-2≥0解得x≥2;3-|x|∈(0,3),根据对数函数为增函数,得到y的最大值为log23,所以集合B为{y|y≤log32}所以A∪B={x|x≥2或x≤log23},所以?UA∪B=(log23,2)故答案为:(log23,2)

网站首页 | 网站地图
All rights reserved Powered by www.mpjx.net
copyright ©right 2010-2021。
内容来自网络,如有侵犯请联系客服。zhit325@qq.com