mpjx.net
当前位置:首页 >> 计算log2(47×25)+log26%log23=______ >>

计算log2(47×25)+log26%log23=______

log2(47×25)+log26-log23=log247+log225+log263=14+5+1=20故答案为:20

由于log23>log22=1,log32<log33=1,∴log23>log32,故答案为>.

因为y=log2x,是单调增函数,所以log25>log23.故答案为:>.

loga(M^n)=nlogaM log(a^n)(M)=1/nlogaM log49=log(2^2)(3^2)=2/2log23=log23

解:log(2)3×log(3)4 =log(2)3×log(2)4/log(2)3 =log(2)4 =log(2)2² =2log(2)2 =2

[log3(2)+log2(3)]^2-log3(2)/log2(3)-log2(3)/log3(2) =[log3(2)+log2(3)]^2-[1/log2(3)]/log2(3)-[1/log3(2)]/log3(2) =[1/log2(3)+1/log3(2)]^2-[1/log2(3)]^2-[1/log3(2)]^2 =2/[log2(3)*log3(2)] =2

∵log21=0,log22=1,log24=2,log2512=log229=9,∴当2n-1≤x<2n时,[log2x]=n-1,即[log22]=[log23]=1,[log24]=[log25]=[log26]=[log27]=2,…∴[log21]+[log22]+[log23]+…+[log2512]=0+1×(22-21)+2×(23-22)+3×(24-23)+4×(25-24)+5×(26-...

:(log23)2?4log23+4+log224=(log23?2)2+log224=(log243)2+log224=log243+log224=log243×24=log232=5.故答案为5.

这个是对数公式

本题结果为3√3.

网站首页 | 网站地图
All rights reserved Powered by www.mpjx.net
copyright ©right 2010-2021。
内容来自网络,如有侵犯请联系客服。zhit325@qq.com